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Leetcode Same Tree

栏目:综合技术时间:2015-04-08 08:21:25

1.题目


Given two binary trees, write a function to check if they are equal or not.

Two binary trees are considered equal if they are structurally identical and the nodes have the same value.


2.解决方案1


class Solution { public: bool isSameTree(TreeNode *p, TreeNode *q) { if(!p && !q) return true; else if(!p && q) return false; else if(p && !q) return false; else { if(p->val != q->val) return false; else { queue<TreeNode*> lq; queue<TreeNode*> rq; lq.push(p); rq.push(q); while(!lq.empty() && !rq.empty()) { TreeNode* lfront = lq.front(); TreeNode* rfront = rq.front(); lq.pop(); rq.pop(); if(!lfront->left && !rfront->left) ;// null else if(!lfront->left && rfront->left) return false; else if(lfront->left && !rfront->left) return false; else { if(lfront->left->val != rfront->left->val) return false; else { lq.push(lfront->left); rq.push(rfront->left); } } if(!lfront->right && !rfront->right) ;// null else if(!lfront->right && rfront->right) return false; else if(lfront->right && !rfront->right) return false; else { if(lfront->right->val != rfront->right->val) return false; else { lq.push(lfront->right); rq.push(rfront->right); } } } return true; } } } };

思路:非常简单,广度遍历便可,就是判断比较繁琐,要左右节点的值都要相同才行。


3.解决方案2


class Solution { public: bool isSameTree(TreeNode *p, TreeNode *q) { if(p == NULL && q == NULL) return true; else if(p == NULL || q == NULL) return false; bool isleftTreeSame = isSameTree(p->left, q->left); bool isrightTreeSame = isSameTree(p->right,q->right); return p->val == q->val && isleftTreeSame && isrightTreeSame; } };

思路:还是递归,比较慢。

http://www.waitingfy.com/archives/1588

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