看看下面代码有何问题：
public static String writeFileToRemote(File file) throws Exception {
PostMethod filePost = new PostMethod(Common.getInstance().getProperty(
"project/remoteFileServer")
+ "/attach?action=upload");
try {
Part[] parts = new Part[4];
parts[0] = new StringPart("FILE_KIND", "2");
parts[1] = new StringPart("RECORD", "true");
parts[2] = new StringPart("FILE_KIND", "2");
parts[3] = new FilePart("FILE_PATH", file.getName(), file);
filePost.setRequestEntity(new MultipartRequestEntity(parts,
filePost.getParams()));
HttpClient client = new HttpClient();
// 由于要上传的文件可能比较大,因此在此设置最大的连接超时时间
client.getHttpConnectionManager().getParams().setConnectionTimeout(
5000);
int status = client.executeMethod(filePost);
String file_path = "";
if (status == HttpStatus.SC_OK) {
// 从
服务器响应的串中获得fileId
String res = filePost.getResponseBodyAsString();
String retFileStr = "retobj.fileId = "";
res = res.substring(res.indexOf(retFileStr)
+ retFileStr.length());
file_path = res.substring(0, res.indexOf('"'))
.replace('|', '/');
}
file.delete();
return file_path;
} catch (Exception e) {
e.printStackTrace();
throw new Exception("写远程文件时出现异常！");
}
}
报错：
Caused by: java.lang.Exception: 写远程文件时出现异常！
com.age.sale.view.tool.ImportTool.writeFileToRemote(ImportTool.java:112)
此时根本没法定位毛病！
因此，应当把try catch去掉，如果要catch，必须把报错信息记录下来！并显示到前台！由于查询日志是很麻烦的1件事情。
本文出自：ouyida3的csdn blog
2015.3.5