problem:
Given an absolute path for a file (Unix-style), simplify it.
For example,
path = "/home/"
, => "/home"
path = "/a/./b/../../c/"
, => "/c"
click to show corner cases.
Corner Cases:
- Did you consider the case where path =
"/../"
?
In this case, you should return "/"
. - Another corner case is the path might contain multiple slashes
'/'
together,
such as "/home//foo/"
.
In this case, you should ignore redundant slashes and return "/home/foo"
.
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Stack String
题意:简化Unix风格路径
thinking:
提示使用stack来做
code:
class Solution {
public:
string simplifyPath(string path) {
stack<string> s;
string str;
for(int i = 0; i < path.size(); i++)
{
if (path[i] == '/')
{
if (str == "..")
{
if (!s.empty())
s.pop();
}
else if (str != "." && str != "")
{
s.push(str);
}
str = "";
}
else
{
str += path[i];
}
}
if (str == "..")
{
if (!s.empty())
s.pop();
}
else if (str != "." && str != "")
s.push(str);
if (s.empty())
return "/";
string ret;
while(!s.empty())
{
ret = "/" + s.top() + ret;
s.pop();
}
return ret;
}
};